Optimal. Leaf size=270 \[ -\frac{4 a^3 \left (4 c^2-5 c d-3 d^2\right ) \sqrt{c+d \sin (e+f x)} E\left (\frac{1}{2} \left (e+f x-\frac{\pi }{2}\right )|\frac{2 d}{c+d}\right )}{3 d^3 f (c+d) \sqrt{\frac{c+d \sin (e+f x)}{c+d}}}-\frac{4 a^3 (2 c-d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{3 d^2 f (c+d)}+\frac{4 a^3 (4 c-5 d) (c-d) \sqrt{\frac{c+d \sin (e+f x)}{c+d}} F\left (\frac{1}{2} \left (e+f x-\frac{\pi }{2}\right )|\frac{2 d}{c+d}\right )}{3 d^3 f \sqrt{c+d \sin (e+f x)}}+\frac{2 (c-d) \cos (e+f x) \left (a^3 \sin (e+f x)+a^3\right )}{d f (c+d) \sqrt{c+d \sin (e+f x)}} \]
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Rubi [A] time = 0.480551, antiderivative size = 270, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.296, Rules used = {2762, 2968, 3023, 2752, 2663, 2661, 2655, 2653} \[ -\frac{4 a^3 \left (4 c^2-5 c d-3 d^2\right ) \sqrt{c+d \sin (e+f x)} E\left (\frac{1}{2} \left (e+f x-\frac{\pi }{2}\right )|\frac{2 d}{c+d}\right )}{3 d^3 f (c+d) \sqrt{\frac{c+d \sin (e+f x)}{c+d}}}-\frac{4 a^3 (2 c-d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{3 d^2 f (c+d)}+\frac{4 a^3 (4 c-5 d) (c-d) \sqrt{\frac{c+d \sin (e+f x)}{c+d}} F\left (\frac{1}{2} \left (e+f x-\frac{\pi }{2}\right )|\frac{2 d}{c+d}\right )}{3 d^3 f \sqrt{c+d \sin (e+f x)}}+\frac{2 (c-d) \cos (e+f x) \left (a^3 \sin (e+f x)+a^3\right )}{d f (c+d) \sqrt{c+d \sin (e+f x)}} \]
Antiderivative was successfully verified.
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Rule 2762
Rule 2968
Rule 3023
Rule 2752
Rule 2663
Rule 2661
Rule 2655
Rule 2653
Rubi steps
\begin{align*} \int \frac{(a+a \sin (e+f x))^3}{(c+d \sin (e+f x))^{3/2}} \, dx &=\frac{2 (c-d) \cos (e+f x) \left (a^3+a^3 \sin (e+f x)\right )}{d (c+d) f \sqrt{c+d \sin (e+f x)}}-\frac{(2 a) \int \frac{(a+a \sin (e+f x)) (a (c-2 d)-a (2 c-d) \sin (e+f x))}{\sqrt{c+d \sin (e+f x)}} \, dx}{d (c+d)}\\ &=\frac{2 (c-d) \cos (e+f x) \left (a^3+a^3 \sin (e+f x)\right )}{d (c+d) f \sqrt{c+d \sin (e+f x)}}-\frac{(2 a) \int \frac{a^2 (c-2 d)+\left (a^2 (c-2 d)-a^2 (2 c-d)\right ) \sin (e+f x)-a^2 (2 c-d) \sin ^2(e+f x)}{\sqrt{c+d \sin (e+f x)}} \, dx}{d (c+d)}\\ &=\frac{2 (c-d) \cos (e+f x) \left (a^3+a^3 \sin (e+f x)\right )}{d (c+d) f \sqrt{c+d \sin (e+f x)}}-\frac{4 a^3 (2 c-d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{3 d^2 (c+d) f}-\frac{(4 a) \int \frac{\frac{1}{2} a^2 (c-5 d) d+\frac{1}{2} a^2 \left (4 c^2-5 c d-3 d^2\right ) \sin (e+f x)}{\sqrt{c+d \sin (e+f x)}} \, dx}{3 d^2 (c+d)}\\ &=\frac{2 (c-d) \cos (e+f x) \left (a^3+a^3 \sin (e+f x)\right )}{d (c+d) f \sqrt{c+d \sin (e+f x)}}-\frac{4 a^3 (2 c-d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{3 d^2 (c+d) f}+\frac{\left (2 a^3 (4 c-5 d) (c-d)\right ) \int \frac{1}{\sqrt{c+d \sin (e+f x)}} \, dx}{3 d^3}-\frac{\left (2 a^3 \left (4 c^2-5 c d-3 d^2\right )\right ) \int \sqrt{c+d \sin (e+f x)} \, dx}{3 d^3 (c+d)}\\ &=\frac{2 (c-d) \cos (e+f x) \left (a^3+a^3 \sin (e+f x)\right )}{d (c+d) f \sqrt{c+d \sin (e+f x)}}-\frac{4 a^3 (2 c-d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{3 d^2 (c+d) f}-\frac{\left (2 a^3 \left (4 c^2-5 c d-3 d^2\right ) \sqrt{c+d \sin (e+f x)}\right ) \int \sqrt{\frac{c}{c+d}+\frac{d \sin (e+f x)}{c+d}} \, dx}{3 d^3 (c+d) \sqrt{\frac{c+d \sin (e+f x)}{c+d}}}+\frac{\left (2 a^3 (4 c-5 d) (c-d) \sqrt{\frac{c+d \sin (e+f x)}{c+d}}\right ) \int \frac{1}{\sqrt{\frac{c}{c+d}+\frac{d \sin (e+f x)}{c+d}}} \, dx}{3 d^3 \sqrt{c+d \sin (e+f x)}}\\ &=\frac{2 (c-d) \cos (e+f x) \left (a^3+a^3 \sin (e+f x)\right )}{d (c+d) f \sqrt{c+d \sin (e+f x)}}-\frac{4 a^3 (2 c-d) \cos (e+f x) \sqrt{c+d \sin (e+f x)}}{3 d^2 (c+d) f}-\frac{4 a^3 \left (4 c^2-5 c d-3 d^2\right ) E\left (\frac{1}{2} \left (e-\frac{\pi }{2}+f x\right )|\frac{2 d}{c+d}\right ) \sqrt{c+d \sin (e+f x)}}{3 d^3 (c+d) f \sqrt{\frac{c+d \sin (e+f x)}{c+d}}}+\frac{4 a^3 (4 c-5 d) (c-d) F\left (\frac{1}{2} \left (e-\frac{\pi }{2}+f x\right )|\frac{2 d}{c+d}\right ) \sqrt{\frac{c+d \sin (e+f x)}{c+d}}}{3 d^3 f \sqrt{c+d \sin (e+f x)}}\\ \end{align*}
Mathematica [A] time = 1.43319, size = 234, normalized size = 0.87 \[ -\frac{2 a^3 (\sin (e+f x)+1)^3 \left (d \cos (e+f x) \left (4 c^2+d (c+d) \sin (e+f x)-5 c d+3 d^2\right )+2 \left (-5 c^2 d+4 c^3-4 c d^2+5 d^3\right ) \sqrt{\frac{c+d \sin (e+f x)}{c+d}} F\left (\frac{1}{4} (-2 e-2 f x+\pi )|\frac{2 d}{c+d}\right )-2 \left (-c^2 d+4 c^3-8 c d^2-3 d^3\right ) \sqrt{\frac{c+d \sin (e+f x)}{c+d}} E\left (\frac{1}{4} (-2 e-2 f x+\pi )|\frac{2 d}{c+d}\right )\right )}{3 d^3 f (c+d) \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )^6 \sqrt{c+d \sin (e+f x)}} \]
Antiderivative was successfully verified.
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Maple [B] time = 1.208, size = 1031, normalized size = 3.8 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a \sin \left (f x + e\right ) + a\right )}^{3}}{{\left (d \sin \left (f x + e\right ) + c\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (3 \, a^{3} \cos \left (f x + e\right )^{2} - 4 \, a^{3} +{\left (a^{3} \cos \left (f x + e\right )^{2} - 4 \, a^{3}\right )} \sin \left (f x + e\right )\right )} \sqrt{d \sin \left (f x + e\right ) + c}}{d^{2} \cos \left (f x + e\right )^{2} - 2 \, c d \sin \left (f x + e\right ) - c^{2} - d^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a \sin \left (f x + e\right ) + a\right )}^{3}}{{\left (d \sin \left (f x + e\right ) + c\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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